Thread: Cancelling Terms Help

In the equation

Ve = sqrt (N m^2/kg^2 kg)/m

With the next step being

Ve = sqrt (N m/kg)

Why do the kg's cancel? I understand why the m's do: They're on opposite sides of the division operator. The kg's however, have me stumped.

An explanation of the involved concept would be helpful...

Originally Posted by Thrawn

In the equation

Ve = sqrt (N m^2/kg^2 kg)/m

With the next step being

Ve = sqrt (N m/kg)

Why do the kg's cancel? I understand why the m's do: They're on opposite sides of the division operator. The kg's however, have me stumped.

An explanation of the involved concept would be helpful...

Maybe this is what you mean.

It seems there are two ways of doing it... at least it seems. What I have, currently, is

Ve = sqrt (Ve = sqrt (N m^2/kg^2 kg)/m

Ve = sqrt (N m/kg)

Ve = sqrt ((kg m/s^2)m/kg)

Ve = sqrt (m/s^2)m

Ve = sqrt (m^2/s^2)

Ve = m/s

Would this be correct? Did I miss a step?

Originally Posted by Thrawn

Would this be correct?

Does it match with mine? No.
Thus, can this be correct? No.

Did I miss a step?

Why does the N "disappear"?
With what can it cancel will.

Originally Posted by ThePerfectHacker

Does it match with mine? No.
Thus, can this be correct? No.

Why does the N "disappear"?
With what can it cancel will.

The N, which stands for newtons, is expanded into its component parts in the next part of equation.

EDIT: The answer should be a unit of velocity...

Originally Posted by Thrawn

It seems there are two ways of doing it... at least it seems. What I have, currently, is

Ve = sqrt (Ve = sqrt (N m^2/kg^2 kg)/m

Ve = sqrt (N m/kg)

Ve = sqrt ((kg m/s^2)m/kg)

Ve = sqrt (m/s^2)m

Ve = sqrt (m^2/s^2)

Ve = m/s

Would this be correct? Did I miss a step?

Please note that your original expression is incorrect:

Ve = sqrt (N m^2/kg^2 kg/m)
Note the placement of the closing parethesis. This is possibly why you are getting an incorrect result.

-Dan