Cancelling Terms Help

• Feb 28th 2007, 07:22 PM
Thrawn
Cancelling Terms Help
In the equation

Ve = sqrt (N m^2/kg^2 kg)/m

With the next step being

Ve = sqrt (N m/kg)

Why do the kg's cancel? I understand why the m's do: They're on opposite sides of the division operator. The kg's however, have me stumped.

An explanation of the involved concept would be helpful...
• Feb 28th 2007, 07:27 PM
ThePerfectHacker
Quote:

Originally Posted by Thrawn
In the equation

Ve = sqrt (N m^2/kg^2 kg)/m

With the next step being

Ve = sqrt (N m/kg)

Why do the kg's cancel? I understand why the m's do: They're on opposite sides of the division operator. The kg's however, have me stumped.

An explanation of the involved concept would be helpful...

Maybe this is what you mean.
• Feb 28th 2007, 07:36 PM
Thrawn
It seems there are two ways of doing it... at least it seems. What I have, currently, is

Ve = sqrt (Ve = sqrt (N m^2/kg^2 kg)/m

Ve = sqrt (N m/kg)

Ve = sqrt ((kg m/s^2)m/kg)

Ve = sqrt (m/s^2)m

Ve = sqrt (m^2/s^2)

Ve = m/s

Would this be correct? Did I miss a step?
• Feb 28th 2007, 07:50 PM
ThePerfectHacker
Quote:

Originally Posted by Thrawn
Would this be correct?

Does it match with mine? No.
Thus, can this be correct? No.
Quote:

Did I miss a step?
Why does the N "disappear"?
With what can it cancel will.
• Feb 28th 2007, 07:52 PM
Thrawn
Quote:

Originally Posted by ThePerfectHacker
Does it match with mine? No.
Thus, can this be correct? No.

Why does the N "disappear"?
With what can it cancel will.

The N, which stands for newtons, is expanded into its component parts in the next part of equation.

EDIT: The answer should be a unit of velocity...
• Mar 1st 2007, 02:54 PM
topsquark
Quote:

Originally Posted by Thrawn
It seems there are two ways of doing it... at least it seems. What I have, currently, is

Ve = sqrt (Ve = sqrt (N m^2/kg^2 kg)/m

Ve = sqrt (N m/kg)

Ve = sqrt ((kg m/s^2)m/kg)

Ve = sqrt (m/s^2)m

Ve = sqrt (m^2/s^2)

Ve = m/s

Would this be correct? Did I miss a step?