Series is 4 + 2 + 1/2 + 1/4 + 1/8
My work:
6 sigma n=1 4(1/2)^n-1
Could it be; 6 sigma m=1 2^n-1 as well?
I'm a little confused, the teachers solutions are:
5 sigma n=0 2^2-n
I've no idea how he got this...
What do you mean?
As far as I know when you start at n=1 then you have to put a"-1" after the n on the right side after sigma and when you start with n=0 you don't need to.
The exponent part of my teachers answer is beyond me. Any clue what he did there, or if my answer is good? He noted that other answers are possible but only listed the one I wrote above.