1. Show (k+1)x^2 - 2x - k = 0 has a solution for all values of k.

So, I find discrim, = 4 + 4k^2 + 4k,

Then I find the discrim of that = -48 = negative, meaning no solutions and graph of first discrim is above x-axis.

How does prove that the original has solutions for all k?

2. Show that ax^2 -(a+b)x + b = 0, has solution for all a, b.

Discriminant is a^2 - 2ab + b^2, how do I interpret that?