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Thread: Log question with negative exponent

  1. December 13th 2009, 12:02 PM #1
    toony
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    Unhappy Log question with negative exponent

    4^x + 6(4^-x) = 5

    Can anyone please help me, I have been trying to solve this for hours
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  2. December 13th 2009, 12:10 PM #2
    Plato
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    Quote Originally Posted by toony View Post
    4^x + 6(4^-x) = 5
    4^x+6\cdot 4^{-x}=5 is same as 4^{2x}-5\cdot 4^x +6 = 0 (we multiply by 4^x).

    Can you solve z^2-5z+6=0?
    If so let each of those z's equal 4^x and solve.
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  3. December 13th 2009, 12:23 PM #3
    toony
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    Wow thanks. didnt notice that !
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