4^x + 6(4^-x) = 5 Can anyone please help me, I have been trying to solve this for hours
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Originally Posted by toony 4^x + 6(4^-x) = 5 $\displaystyle 4^x+6\cdot 4^{-x}=5$ is same as $\displaystyle 4^{2x}-5\cdot 4^x +6 = 0$ (we multiply by $\displaystyle 4^x$). Can you solve $\displaystyle z^2-5z+6=0?$ If so let each of those $\displaystyle z's$ equal $\displaystyle 4^x$ and solve.
Wow thanks. didnt notice that !
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