I need to determine a value of K for which the system has infinity many solutions 3x+4y=12 x+ky=4 Then x=4-(4/3)y 4-(4/3)y+ky=4 -(4/3)y+ky=0 So if k=4/3, then y=y?
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Originally Posted by cognoscente I need to determine a value of K for which the system has infinity many solutions 3x+4y=12 x+ky=4 Then x=4-(4/3)y 4-(4/3)y+ky=4 -(4/3)y+ky=0 So if k=4/3, then y=y? If you multiply both sides of the second equation by 3, you'll see . For the system to have infinitely many solutions, the equations would have to be identically equal. That means and so .
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