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Math Help - Algebraic fraction?

  1. #1
    Junior Member
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    Algebraic fraction?

    Solve the simultaneous equations
     2x + y - z = 3<br />
3x + 2y + 2z = 13<br />
x - 3y+ z = -6
    and deduce the soltuions of the simultaneous equations.
     2/(a+3)  +  1/(b-2)  -  1/(1-c) = 3
    3/(a+3)  +  2/(b-2)  +  2/(1 - c) = 13
    1/(a+3)  - 3/(b-2)  +  1/(1-c) = -6
    (sorry i dont know how to do fractions.)

    I've solved the simultaneous equations. x = 1, y =3, z =2
    but for the second part I dont know what to do. Can anyone help me please?
    Thanks.
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  2. #2
    MHF Contributor
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    Quote Originally Posted by Detanon View Post
    Solve the simultaneous equations
     2x + y - z = 3<br />
3x + 2y + 2z = 13<br />
x - 3y+ z = -6
    and deduce the soltuions of the simultaneous equations.
     2/(a+3)  +  1/(b-2)  -  1/(1-c) = 3
    3/(a+3)  +  2/(b-2)  +  2/(1 - c) = 13
    1/(a+3)  - 3/(b-2)  +  1/(1-c) = -6
    (sorry i dont know how to do fractions.)

    I've solved the simultaneous equations. x = 1, y =3, z =2
    but for the second part I dont know what to do. Can anyone help me please?
    Thanks.
    Call the equation 1,2 and 3 in the order you listed them vertically. Add equation1+equation3 and you get an equation with just variables a and b. Take 2*equation1+equation2 and again the c variable drops out. Solve the two variable system and then figure out c.
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  3. #3
    Junior Member
    Joined
    Dec 2009
    Posts
    61
    Can you explain the steps in more detail please, I dont really get what to do. Thanks!
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