If f(x) = 2x+1,
write as a single fraction f (x+1)/ f (x-1) - f(x-1)/ f (x+1).
Can someone help me with this please. I have the solution where the f (x + 1)
turns to 2(x+1) +1 but I dont get how you get to that.
IF $\displaystyle f(x) = 2x+1$
$\displaystyle
\frac{f (x+1)}{f (x-1)} - \frac{f(x-1)}{f (x+1)}
$
plug in what is inside the $\displaystyle f(...) $into $\displaystyle 2x+1$ where the x is
like this
$\displaystyle \frac{2(x+1)+1}{2(x-1)+1}- \frac{2(x-1) +1}{2(x+1) +1}$
the rest is just algebra of combining 2 fractions