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Thread: quotient of functions

  1. #1
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    quotient of functions

    I forgot what these are called but when it comes to these, i get wayyy lost and just dont know what to do.

    $\displaystyle (1 - x)/(1 + x)=100$

    Thanks for the help!
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by hydride View Post
    I forgot what these are called but when it comes to these, i get wayyy lost and just dont know what to do.

    $\displaystyle (1 - x)/(1 + x)=100$

    Thanks for the help!
    These are called equations. Don't be lost my friend, just multiply both sides by $\displaystyle (1+x)$. Then distibute the $\displaystyle 100$, and isolate $\displaystyle x.$
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  3. #3
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    Quote Originally Posted by VonNemo19 View Post
    These are called equations. Don't be lost my friend, just multiply both sides by $\displaystyle (1+x)$. Then distibute the $\displaystyle 100$, and isolate $\displaystyle x.$

    Tell me the answer is $\displaystyle x = -99/100$
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  4. #4
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by hydride View Post
    Tell me the answer is $\displaystyle x = -99/100$
    Yes.
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  5. #5
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    $\displaystyle
    \frac{1 - x}{1 + x}=100
    $

    $\displaystyle
    1-x=100(1+x)
    $

    $\displaystyle
    1-x=100+100x
    $

    $\displaystyle
    1-100=100x+x
    $

    $\displaystyle
    -99=101x
    $

    $\displaystyle
    \frac{-99}{101}=x
    $
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  6. #6
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    EDIT: EDIT: alriiiight. Thanks a whole bunch.
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  7. #7
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    Quote Originally Posted by hydride View Post
    EDIT: EDIT: alriiiight. Thanks a whole bunch.
    No, the answer is:

    $\displaystyle

    \frac{-99}{101}=x
    $
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  8. #8
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    Quote Originally Posted by millerst View Post
    No, the answer is:

    $\displaystyle

    \frac{-99}{101}=x
    $

    LOL, sorry, i just forgot to add the 1, but i did have it when i solved it. Thanks again.
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