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Thread: Simplifying the Radical?

  1. December 11th 2009, 05:42 PM #1
    deekay930
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    Simplifying the Radical?

    I really don't understand how to work this problem out. I usually just use my calculator but my instructor (online student) wants me to show work.

    √ 150x^5y^8

    √ 20x^4 *√ 5x
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  2. December 11th 2009, 05:55 PM #2
    dedust
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    Quote Originally Posted by deekay930 View Post
    I really don't understand how to work this problem out. I usually just use my calculator but my instructor (online student) wants me to show work.

    √ 150x^5y^8

    √ 20x^4 *√ 5x
    \sqrt{150x^4xy^8}= \sqrt{(25)(6)x^4xy^8}=5x^2y^4 \sqrt{6x}

    \sqrt{20x^4} \sqrt{5x}=\sqrt{100x^4x}=10x^2 \sqrt{x}
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