I need to determine a value of K for which the system has no solutions
2x-y=3
4x+ky=4
So,
y=-3/2x
k=10/y
x=-3/2
y=6
Therefore, K=-5/3
With all these values, I found that the system has a unique solution of K=-5/3 at the point (-3/2,-6)
How would I go about finding a value of K for which there is no solution? Is it just any value on the real number line that does not equal -5/3?