where does the function cut the yintercept f(x) =

+2?

or when I get the f '(x) -9?

Printable View

- Dec 10th 2009, 12:16 PMwolfhoundcut the y intercept
where does the function cut the yintercept f(x) =

+2?

or when I get the f '(x) -9? - Dec 10th 2009, 12:17 PMstapel
I've never heard that terminology. I will guess that "cut the y-intercept" means something like "cuts" (or crosses) "the y-axis". If this is correct, then you need to plug zero in for x to find the y-value of the y-intercept. (Wink)

I don't know what you're trying to do with the derivative, so I'm afraid I cannot comment on that. Sorry! (Blush) - Dec 10th 2009, 12:43 PMwolfhound
- Dec 10th 2009, 01:29 PMRaoh
- Dec 10th 2009, 03:06 PMBabyMilo
- Dec 10th 2009, 03:14 PMwolfhound