1. ## multiple choice question

If $\frac{16^x}{\frac{1}{2} x^2}-32=0$, then $x=$

(a) -1 or -4

(b) 1 or -5

(c) 2 or -4

(d) -2 or 4

2. Originally Posted by ibnashraf
If $\frac{16^x}{\frac{1}{2} x^2}-32=0$, then $x=$

(a) -1 or -4

(b) 1 or -5

(c) 2 or -4

(d) -2 or 4

I can only get

x = 1

which is not one of the choices

3. I would advise graphing this equation and seeing where they cross the $x$ axis.

Equivalently, you could graph

$y = 16^x$ and $16x^2$ and see where they intersect.

4. actually that's how i interpreted the question to be since it wasn't clearly written. This is exactly how i saw it written down:

$16^x/\frac{1}{2}x^2-32=0$

So is there any way that the above question can be "interpreted" to give one of the 4 responses mentioned previously?

5. as Prove IT suggested to graph it

did graph this and none of answers showed except x = 1 is the only interger value

and got 1/2

its a strange multiple choice

6. Originally Posted by ibnashraf
actually that's how i interpreted the question to be since it wasn't clearly written. This is exactly how i saw it written down:

$16^x/\frac{1}{2}x^2-32=0$

So is there any way that the above question can be "interpreted" to give one of the 4 responses mentioned previously?
The only answers I can see are 1 and 1/2. Putting it into Maple confirms, as well as another way funky answer. None of these are of course a choice. Something tells me the problem might be written down wrong?