If $\displaystyle \frac{16^x}{\frac{1}{2} x^2}-32=0$, then $\displaystyle x=$
(a) -1 or -4
(b) 1 or -5
(c) 2 or -4
(d) -2 or 4
actually that's how i interpreted the question to be since it wasn't clearly written. This is exactly how i saw it written down:
$\displaystyle 16^x/\frac{1}{2}x^2-32=0$
So is there any way that the above question can be "interpreted" to give one of the 4 responses mentioned previously?