What should be the value of the fourth column?
call red is R, yellow is Y and blue is B
so on the first column we have $\displaystyle 2R+Y+B=43$
second column we have $\displaystyle Y+3B=55$
last column we have $\displaystyle 3R+B=45$
so you have
$\displaystyle 2R+Y+B=43$
$\displaystyle Y+3B=55$
$\displaystyle 3R+B=45$
then you can find R, B, and Y by yourself. try this and talk your answer.
Hello, Mukilab!
We have a system of equations:What should be the value of the fourth column?
. . $\displaystyle \begin{array}{ccccc}\text{Column 1:} & 2R + Y + B &=& 43 \\ \text{Column 2:} & R \qquad+ 3B &=& 55 \\ \text{Colukn 3:} & 3R \qquad + B &=& 45 \end{array}$
Solution: .$\displaystyle R = 10,\;Y = 8,\;B = 15$
Columkn 4: .$\displaystyle R + Y + B + Y \;=\;10+8+15+8\;=\;41$