factor

**taemonique** · December 8th 2009, 09:09 AM

3v^3-192

factor completely

**TheEmptySet** · December 8th 2009, 09:11 AM

Originally Posted by taemonique

3v^3-192

factor completely

Factor out a 3 from each term, then use the difference of cubes formula

$3(v^3-64)$

remember that

$a^3-b^3=(a-b)(a^2+ab+b^2)$

**taemonique** · December 8th 2009, 09:13 AM

so what is the answer? because that isnt factored completely

**doomgaze** · December 8th 2009, 09:16 AM

Originally Posted by taemonique

so what is the answer? because that isnt factored completely

use the formula he gave you, you want to learn how to do it not just get the answer.

**taemonique** · December 8th 2009, 09:19 AM

i did that much already. I dont see how to completly fctor it out

**manhmanh17vn** · December 8th 2009, 11:40 AM

$3V^3-192=3(V^3-64)=3(V^3-4^3)=?$
use this :

and finish this by yourself.

**Mukilab** · December 8th 2009, 11:47 AM

Forgive me if I am incorrect. Not completely sure with factorising but I chanced upon this.

Without using the $4^3$ but using the technique showed I got

$3v^3-192=...$ then $(3v-64)(3v^2+(3v*64)+64^2)$

**manhmanh17vn** · December 8th 2009, 11:53 AM

Originally Posted by Mukilab

Forgive me if I am incorrect. Not completely sure with factorising but I chanced upon this.

Without using the $4^3$ but using the technique showed I got

$3v^3-192=...$ then $(3v-64)(3v^2+(3v*64)+64^2)$

this is incorrect. you need think against.

**Mukilab** · December 8th 2009, 11:58 AM

Probably because I didn't account for the $4^3$

Can you account for my mistake?

I'll try again

then

$3v^3-192=....$ then $(3v-4^3)(3v^2+(3v4^3)+4^6)$

What's the multiplication sign in latex?

**mr fantastic** · December 8th 2009, 12:02 PM

Originally Posted by Mukilab

Probably because I didn't account for the $4^3$

Can you account for my mistake?

I'll try again

then

$3v^3-192=....$ then $(3v-4^3)(3v^2+(3v4^3)+4^6)$

What's the multiplication sign in latex?

You have been told exactly what to do. Go back. Read post #2. For your question, what is a? What is b? Substitute. Get the answer.

**Mukilab** · December 8th 2009, 12:09 PM

Finally?

$\Rightarrow 3v^3-192$

$3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)$

**mr fantastic** · December 8th 2009, 12:14 PM

Originally Posted by Mukilab

Finally?

$\Rightarrow 3v^3-192$

$3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)$

How can this possibly be correct!? Do what I said in post #8. Show all your working - every single step, starting with what is a and what is b.

**Mukilab** · December 8th 2009, 12:20 PM

3v^3-192

^^^
original

a= $3v^3$
b= $-192$

$a^3=3v^3x^3=^9$ , final answer is $3v^9 = a^3$
$b^3=-192^3$

$3v^9-192^3=(3v^3-192)(3v^6+(3v^3x(-192))-192^2)$

**Mukilab** · December 8th 2009, 12:22 PM

Sorry for the x's, I do not know how to input multiplication

**manhmanh17vn** · December 8th 2009, 12:32 PM

Originally Posted by Mukilab

Finally?

$\Rightarrow 3v^3-192$

$3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)$

Originally Posted by Mukilab

Sorry for the x's, I do not know how to input multiplication

Originally Posted by Mukilab

3v^3-192

^^^
original

a= $3v^3$
b= $-192$

$a^3=3v^3x^3=^9$ , final answer is $3v^9 = a^3$
$b^3=-192^3$

$3v^9-192^3=(3v^3-192)(3v^6+(3v^3x(-192))-192^2)$

ok that's ok this is problem. i need help you

firstt this you the the number 192 you can you use calculator to see $192=3*4^3$
and change this into the $3v^3-192$ so you have $3v^3- 3*4^3$ $\Longrightarrow 3(v^3-4^3)$
remember you have

so $a=v, b=4$
yoou can find this when you change into the

Thread: factor

LinkBack

Thread Tools

Display

factor

Similar Math Help Forum Discussions

Histograms scale factor.. bins statistics and scale factor multiplication...?

factor analysis , extract second factor loading

factor analysis , extract second factor loading

Factor 3x^2 +2x -6

How do i factor this?

Search Tags