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Math Help - factor

  1. #1
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    factor

    3v^3-192

    factor completely
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by taemonique View Post
    3v^3-192

    factor completely
    Factor out a 3 from each term, then use the difference of cubes formula

    3(v^3-64)

    remember that

    a^3-b^3=(a-b)(a^2+ab+b^2)
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  3. #3
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    so what is the answer? because that isnt factored completely
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  4. #4
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    Quote Originally Posted by taemonique View Post
    so what is the answer? because that isnt factored completely
    use the formula he gave you, you want to learn how to do it not just get the answer.
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  5. #5
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    i did that much already. I dont see how to completly fctor it out
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  6. #6
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    3V^3-192=3(V^3-64)=3(V^3-4^3)=?
    use this :
    and finish this by yourself.
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  7. #7
    Senior Member Mukilab's Avatar
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    Forgive me if I am incorrect. Not completely sure with factorising but I chanced upon this.

    Without using the 4^3 but using the technique showed I got

    3v^3-192=...then (3v-64)(3v^2+(3v*64)+64^2)
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  8. #8
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    Quote Originally Posted by Mukilab View Post
    Forgive me if I am incorrect. Not completely sure with factorising but I chanced upon this.

    Without using the 4^3 but using the technique showed I got

    3v^3-192=...then (3v-64)(3v^2+(3v*64)+64^2)
    this is incorrect. you need think against.
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  9. #9
    Senior Member Mukilab's Avatar
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    Probably because I didn't account for the 4^3

    Can you account for my mistake?

    I'll try again

    then

    3v^3-192=....then (3v-4^3)(3v^2+(3v4^3)+4^6)

    What's the multiplication sign in latex?
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  10. #10
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    Quote Originally Posted by Mukilab View Post
    Probably because I didn't account for the 4^3

    Can you account for my mistake?

    I'll try again

    then

    3v^3-192=....then (3v-4^3)(3v^2+(3v4^3)+4^6)

    What's the multiplication sign in latex?
    You have been told exactly what to do. Go back. Read post #2. For your question, what is a? What is b? Substitute. Get the answer.
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  11. #11
    Senior Member Mukilab's Avatar
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    Finally?

    \Rightarrow 3v^3-192




    3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)
    Last edited by mr fantastic; December 8th 2009 at 12:12 PM. Reason: Fixed latex
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  12. #12
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    Quote Originally Posted by Mukilab View Post
    Finally?

    \Rightarrow 3v^3-192




    3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)
    How can this possibly be correct!? Do what I said in post #8. Show all your working - every single step, starting with what is a and what is b.
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  13. #13
    Senior Member Mukilab's Avatar
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    3v^3-192

    ^^^
    original

    a= 3v^3
    b= -192

    a^3=3v^3x^3=^9, final answer is 3v^9 = a^3
    b^3=-192^3




    3v^9-192^3=(3v^3-192)(3v^6+(3v^3x(-192))-192^2)
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  14. #14
    Senior Member Mukilab's Avatar
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    Sorry for the x's, I do not know how to input multiplication
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  15. #15
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    Quote Originally Posted by Mukilab View Post
    Finally?

    \Rightarrow 3v^3-192




    3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)
    Quote Originally Posted by Mukilab View Post
    Sorry for the x's, I do not know how to input multiplication
    Quote Originally Posted by Mukilab View Post
    3v^3-192

    ^^^
    original

    a= 3v^3
    b= -192

    a^3=3v^3x^3=^9, final answer is 3v^9 = a^3
    b^3=-192^3




    3v^9-192^3=(3v^3-192)(3v^6+(3v^3x(-192))-192^2)
    ok that's ok this is problem. i need help you

    firstt this you the the number 192 you can you use calculator to see 192=3*4^3
    and change this into the 3v^3-192so you have 3v^3- 3*4^3 \Longrightarrow 3(v^3-4^3)
    remember you have
    so a=v, b=4
    yoou can find this when you change into the
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