3v^3-192

factor completely

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- Dec 8th 2009, 09:09 AMtaemoniquefactor
3v^3-192

factor completely - Dec 8th 2009, 09:11 AMTheEmptySet
- Dec 8th 2009, 09:13 AMtaemonique
so what is the answer? because that isnt factored completely(Doh)

- Dec 8th 2009, 09:16 AMdoomgaze
- Dec 8th 2009, 09:19 AMtaemonique
i did that much already. I dont see how to completly fctor it out

- Dec 8th 2009, 11:40 AMmanhmanh17vn
$\displaystyle 3V^3-192=3(V^3-64)=3(V^3-4^3)=?$

use this :http://www.mathhelpforum.com/math-he...a6b5924a-1.gif

and finish this by yourself. - Dec 8th 2009, 11:47 AMMukilab
Forgive me if I am incorrect. Not completely sure with factorising but I chanced upon this.

Without using the $\displaystyle 4^3$ but using the technique showed I got

$\displaystyle 3v^3-192=...$then$\displaystyle (3v-64)(3v^2+(3v*64)+64^2)$ - Dec 8th 2009, 11:53 AMmanhmanh17vn
- Dec 8th 2009, 11:58 AMMukilab
Probably because I didn't account for the $\displaystyle 4^3$

Can you account for my mistake?

I'll try again

http://www.mathhelpforum.com/math-he...00453775-1.gifthenhttp://www.mathhelpforum.com/math-he...9627459a-1.gif

$\displaystyle 3v^3-192=....$then$\displaystyle (3v-4^3)(3v^2+(3v4^3)+4^6)$

What's the multiplication sign in latex? - Dec 8th 2009, 12:02 PMmr fantastic
- Dec 8th 2009, 12:09 PMMukilab
Finally?

http://www.mathhelpforum.com/math-he...c0888190-1.gif$\displaystyle \Rightarrow 3v^3-192$

http://www.mathhelpforum.com/math-he...a6b5924a-1.gif

$\displaystyle 3v^9-64^9 \Rightarrow = (3v^3-64^3)(3v^6+3v^3(-64^3)-64^6)$ - Dec 8th 2009, 12:14 PMmr fantastic
- Dec 8th 2009, 12:20 PMMukilab
3v^3-192

^^^

original

a=$\displaystyle 3v^3$

b=$\displaystyle -192$

$\displaystyle a^3=3v^3x^3=^9$, final answer is $\displaystyle 3v^9 = a^3$

$\displaystyle b^3=-192^3$

http://www.mathhelpforum.com/math-he...a6b5924a-1.gif

$\displaystyle 3v^9-192^3=(3v^3-192)(3v^6+(3v^3x(-192))-192^2)$ - Dec 8th 2009, 12:22 PMMukilab
Sorry for the x's, I do not know how to input multiplication

- Dec 8th 2009, 12:32 PMmanhmanh17vn
ok that's ok this is problem. i need help you

firstt this you the the number 192 you can you use calculator to see $\displaystyle 192=3*4^3$

and change this into the $\displaystyle 3v^3-192$so you have $\displaystyle 3v^3- 3*4^3$$\displaystyle \Longrightarrow 3(v^3-4^3)$

remember you have http://www.mathhelpforum.com/math-he...a6b5924a-1.gif

so $\displaystyle a=v, b=4$

yoou can find this when you change into the http://www.mathhelpforum.com/math-he...a6b5924a-1.gif