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Math Help - How do you solve this division

  1. #1
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    Ontario Canada
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    How do you solve this division

    (16a^3-17a+10)/ (4a+5)

    I have to solve this operation. I should have a quotient and remainder??


    How do I solve this?
    Thanks
    Joanne
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  2. #2
    Senior Member
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    <br />
16 a^3 -17a+10 = (4a+5)(something)<br />

    In order to get a term on the left like <br />
16 a^3<br />
the 4a has to multiply 4a^2, so let's try:

    <br />
16 a^3 -17a+10 = (4a+5)(4a^2+something)<br />

    Unfortunately now the right hand side (RHS) is:
    <br />
16 a^3 +20a^2+something<br />

    We don't want the <br />
 20a^2 . So let's modify the 'something'. We have to multiply the 4a by -5a to get a -20a^2.

    So the equation is now

    <br />
16 a^3 -17a+10 = (4a+5)(4a^2-5a+something)<br />

    We've added an a^2 term and an a term. The last term to add is a constant term.

    Can you find the last constant in the right hand side? Whatever is left over is the remainder in your division.
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