hi can someone help me verifty if this is right? is there a way to put the squared sign in here? 2xsquared - 4x - 5 = 0 my answer was 4± √14
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Thats wrong Try your -b formula again x=2.87 or -0.87
Originally Posted by likewhoa hi can someone help me verifty if this is right? is there a way to put the squared sign in here? 2xsquared - 4x - 5 = 0 my answer was 4± √14 I've got a different solution. I assume that you used the quadratic formula to solve the equation(?). If so you have: $\displaystyle x = \dfrac{4 \pm \sqrt{16-4 \cdot 2 \cdot (-5)}}{2 \cdot 2}$ Now simplify. Spoiler: You should now have $\displaystyle x = 1\pm\frac12 \sqrt{14}$
Im using the quadratic formula
so you dont combine everything inside the radical then divide?
Originally Posted by likewhoa so you dont combine everything inside the radical then divide? Originally Posted by earboth you have: $\displaystyle x = \dfrac{4 \pm \sqrt{16-4 \cdot 2 \cdot (-5)}}{2 \cdot 2}$ ... It is now plain arithmetic: $\displaystyle x = \dfrac{4 \pm \sqrt{16+40}}{2 \cdot 2}$ $\displaystyle x = \dfrac{4 \pm \sqrt{56}}{4}$ $\displaystyle x = \dfrac{4 \pm 2 \cdot \sqrt{14}}{4}$ $\displaystyle x = 1 \pm \frac12 \cdot \sqrt{14}$
ahhh okok thx
Originally Posted by likewhoa hi can someone help me verifty if this is right? is there a way to put the squared sign in here? 2xsquared - 4x - 5 = 0 my answer was 4± √14 Nobody mentioned how to put the squared sign in. Type: [tex]2x^2-4x-5=0[ /math] Erase the space before the /math and you get $\displaystyle 2x^2-4x-5=0$
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