1) The income of A,B and C are in the ratio of 7:9:12 and their spending are in the ratio of 8:9:15. If A saves 1/4th of his income, then the savings of A, B,C are in the ratio of?
2) A diamond falls down and breaks into three pieces whose weights are in the ratio 2:3:5. The value of diamond is proportionate to the square of it's weight. If the value of the original diamond is $20,000, what is the loss in value due to breakage?
How do i solve these?
Hello saberteeth1) Consider a total income of £Originally Posted by saberteeth
. Of this, A's income is £
and he saves
of it. So he saves £
. He spends
of it; so he spends £
.
B's income is £, and his spend is
of A's spend. So he spends £
£
. Therefore he saves £
£
.
I'll leave you to work out C's spend and saving in the same way.
When you've done that, write the savings as a ratio, and simplify the result. I reckon the final answer is
.
2). So the weight of the smallest piece is
of the weight of the original single diamond. So its value is the square of this fraction multiplied by the original value, which is:
$Work out the value of the other two pieces in the same way. Add these values together, and subtract from $$
to find the total loss in value. I reckon the answer is $
.
Grandad
I make that 56:99:69When you've done that, write the savings as a ratio
I reckon the final answer is
Grandad
Which one of us grandads is correct?
224 288 384
168 189 315
=== === ===
056 099 069
Hello WilmerI've just done it again, and gotI make that 56:99:78
Which one of us grandads is correct?
.. So, if that's right, then neither of us was correct! (In my first attempt I dropped a digit and worked out
instead of
.)
Do you agree?
Grandad
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