How would you go about solving this?
(3x^1/4)^3
__________
x^1/12
Sorry it doesnt look nice. :/
not solving, simplifying ...
$\displaystyle \frac{(3x^{\frac{1}{4}})^3}{x^{\frac{1}{12}}}$
$\displaystyle \frac{27x^{\frac{3}{4}}}{x^{\frac{1}{12}}}$
$\displaystyle \frac{27x^{\frac{9}{12}}}{x^{\frac{1}{12}}}$
$\displaystyle 27x^{\frac{8}{12}}$
$\displaystyle 27x^{\frac{2}{3}}$