How would you go about solving this?

(3x^1/4)^3

__________

x^1/12

Sorry it doesnt look nice. :/

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- Dec 4th 2009, 03:49 PMleoslickSimplifying given expression
How would you go about solving this?

(3x^1/4)^3

__________

x^1/12

Sorry it doesnt look nice. :/ - Dec 4th 2009, 04:17 PMskeeter
not solving, simplifying ...

$\displaystyle \frac{(3x^{\frac{1}{4}})^3}{x^{\frac{1}{12}}}$

$\displaystyle \frac{27x^{\frac{3}{4}}}{x^{\frac{1}{12}}}$

$\displaystyle \frac{27x^{\frac{9}{12}}}{x^{\frac{1}{12}}}$

$\displaystyle 27x^{\frac{8}{12}}$

$\displaystyle 27x^{\frac{2}{3}}$