I this is the problem and the solution.
[1/2(10/3)]^2= 25/9
The ways I have worked it out so far are not generating 25/9 so if you could help me by telling me the steps to get there it would be great. thanks
Using LaTeX or the brackets correctly helps.
$\displaystyle \left[\frac{1}{2}\left(\frac{10}{3}\right)\right]^2 = \left(\frac{1}{2}\right)^2 \left(\frac{10}{3}\right)^2$
$\displaystyle = \frac{1^2}{2^2}\left(\frac{10^2}{3^2}\right)$
$\displaystyle = \frac{1}{4}\left(\frac{100}{9}\right)$
$\displaystyle = \frac{25}{9}$.
I'll make it easy
just multiply $\displaystyle \frac {1}{2} $ by $\displaystyle \frac {10}{3}$
Not we got $\displaystyle (\frac {10}{6})^2$
The rest should be easy:
$\displaystyle \frac {10^2}{6^2} $
$\displaystyle \frac {100}{36} $
simplify:
$\displaystyle \frac {25}{9} $
done.