Results 1 to 3 of 3

Math Help - help wit evaluating integers please?

  1. #1
    Newbie
    Joined
    Dec 2009
    From
    Singapore
    Posts
    2

    Smile help wit evaluating integers please?

    hello everyone(:
    im new to this forum, and just starting to practice my maths caause i will be taking my GCSEs next year and i really need to cause i failed my maths this year and i dont want it to happen again.
    i am currently practicing problems on integers, and i need help on this problem.
    a step-by-step solution wit explanations would be loved,

    √-27 x (-3/2) ^ -1 + 9 ^3/2

    th questions says ; Evaluate the following without using a calculator.
    thanks for all th help, however small it may be, it still helps(:
    Last edited by mr fantastic; December 4th 2009 at 03:40 AM. Reason: Enlarged the microscopic font size to default size.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,831
    Thanks
    1602
    Quote Originally Posted by ohshafiqa View Post
    hello everyone(:
    im new to this forum, and just starting to practice my maths caause i will be taking my GCSEs next year and i really need to cause i failed my maths this year and i dont want it to happen again.
    i am currently practicing problems on integers, and i need help on this problem.
    a step-by-step solution wit explanations would be loved,

    √-27 x (-3/2) ^ -1 + 9 ^3/2

    th questions says ; Evaluate the following without using a calculator.
    thanks for all th help, however small it may be, it still helps(:

    It really helps if you use LaTeX or brackets so that we know what you're asking.

    Are you asked to evaluate

    \sqrt[3]{-27} \times \left(-\frac{3}{2}\right)^{-1} + 9^{\frac{3}{2}}?


    If so...

    \sqrt[3]{-27} = -3.

    \left(-\frac{3}{2}\right)^{-1} = -\frac{2}{3}.

    9^{\frac{3}{2}} = (\sqrt{9})^3 = 3^3 = 27.


    You should be able to go from here.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Dec 2009
    From
    Singapore
    Posts
    2
    hey thanks yep from there i tried working it out and i got th answer(:

    thanks again!
    Last edited by mr fantastic; December 4th 2009 at 03:40 AM. Reason: Changed font size from microscopic size
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: December 6th 2011, 12:47 AM
  2. Replies: 7
    Last Post: August 3rd 2010, 02:31 PM
  3. Matrix of integers whose inverse is full of integers
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: March 19th 2010, 03:02 PM
  4. Replies: 4
    Last Post: February 24th 2008, 04:08 PM
  5. Replies: 2
    Last Post: October 14th 2007, 04:18 PM

Search Tags


/mathhelpforum @mathhelpforum