1. ## help wit evaluating integers please?

hello everyone(:
im new to this forum, and just starting to practice my maths caause i will be taking my GCSEs next year and i really need to cause i failed my maths this year and i dont want it to happen again.
i am currently practicing problems on integers, and i need help on this problem.
a step-by-step solution wit explanations would be loved,

³√-27 x (-3/2) ^ -1 + 9 ^3/2

th questions says ; Evaluate the following without using a calculator.
thanks for all th help, however small it may be, it still helps(:

2. Originally Posted by ohshafiqa
hello everyone(:
im new to this forum, and just starting to practice my maths caause i will be taking my GCSEs next year and i really need to cause i failed my maths this year and i dont want it to happen again.
i am currently practicing problems on integers, and i need help on this problem.
a step-by-step solution wit explanations would be loved,

³√-27 x (-3/2) ^ -1 + 9 ^3/2

th questions says ; Evaluate the following without using a calculator.
thanks for all th help, however small it may be, it still helps(:

It really helps if you use LaTeX or brackets so that we know what you're asking.

$\displaystyle \sqrt[3]{-27} \times \left(-\frac{3}{2}\right)^{-1} + 9^{\frac{3}{2}}$?

If so...

$\displaystyle \sqrt[3]{-27} = -3$.

$\displaystyle \left(-\frac{3}{2}\right)^{-1} = -\frac{2}{3}$.

$\displaystyle 9^{\frac{3}{2}} = (\sqrt{9})^3 = 3^3 = 27$.

You should be able to go from here.

3. hey thanks yep from there i tried working it out and i got th answer(:

thanks again!