How can I factorise the following? I am new to more complex forms of factorisation and am teaching myself at home. 1. 4p^5q^3 + 6p^2q^4 2. 3(x+6)^2 - 9(x-6) 3. 12a^4 - 3 4. 36p^3 - 25pq^2 5. 2x^2 + x -21
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Originally Posted by JadeKiara How can I factorise the following? I am new to more complex forms of factorisation and am teaching myself at home. 1. 4p^5q^3 + 6p^2q^4 2. 3(x+6)^2 - 9(x-6) 3. 12a^4 - 3 4. 36p^3 - 25pq^2 5. 2x^2 + x -21 the first one is not sure if the 2nd one is typed ok the 3rd one is do you see what is happening???
Last edited by bigwave; December 3rd 2009 at 10:32 PM.
By the way, the 2nd one is in its original form from the textbook. Ah! This is definitely an aid in my understanding. But I just have to become accustomed to putting into practice by myself. So, correct me if I am wrong: (6p^2-5pq)(6p+5q) No, it's not right. I am baffled by this one.
first factor out what has exponents so factor out p this will factor into a difference of squares has the fog cleared
the last one, .
looks good to me
Any ideas about number 2?
Originally Posted by Raoh the last one, . Yes, I did manage to work this one out by myself. All except number 2. Thanks for your help!
Originally Posted by JadeKiara Yes, I did manage to work this one out by myself. All except number 2. Thanks for your help! given: first expand the brackets combine like terms factor out 3 hope this helps..
Last edited by bigwave; December 4th 2009 at 03:40 PM. Reason: math correction
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