Hello, I cannot recall my algebra.

how does this go from

n(n+1)/2 +(n+1)

to

n(n+1) + 2(n+1)/2

I'm missing a step in between. Can anyone show me? thank you. (Nod)

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- Dec 3rd 2009, 04:30 PMtigertinaalgebraic steps
Hello, I cannot recall my algebra.

how does this go from

n(n+1)/2 +(n+1)

to

n(n+1) + 2(n+1)/2

I'm missing a step in between. Can anyone show me? thank you. (Nod) - Dec 3rd 2009, 04:40 PMStroodle
Hi there.

Do you mean:

$\displaystyle \frac{n(n+1)}{2}+(n+1)$ ?

If so, you can't change it to $\displaystyle n(n+1)+\frac{2(n+1)}{2}$, as the first term is now different.

You could however change it to $\displaystyle \frac{n(n+1)}{2}+\frac{2(n+1)}{2}$, as you are just multiplying the second term by $\displaystyle \frac{2}{2}$ which equals $\displaystyle 1$.

Hope this helps :) - Dec 3rd 2009, 04:42 PMtigertina
it does, thank you (Nod)