Solve for m: $\displaystyle (t/V)=sqrt(cb/m)$ $\displaystyle (t/V)^2=(cb/m)$ what from there?
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Originally Posted by m0nkeysensei Solve for m: $\displaystyle (t/V)=sqrt(cb/m)$ $\displaystyle (t/V)^2=(cb/m)$ what from there? $\displaystyle \frac{t^2}{V^2}=\frac{cb}{m} $ $\displaystyle m=\frac{c\times b\times V^2}{t^2} $
how did you flip $\displaystyle \frac {t}{v}$ to $\displaystyle \frac {v}{t}$ and how did you move the CB over ?
Originally Posted by m0nkeysensei how did you flip $\displaystyle \frac {t}{v}$ to $\displaystyle \frac {v}{t}$ and how did you move the CB over ? He cross multiplied
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