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Math Help - Solving quadratic equations/square root property

  1. #1
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    Solving quadratic equations/square root property

    How do I solve these using the square root property?

    x^2+4x+4=9

    (x-5)^2=25
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  2. #2
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    Quote Originally Posted by mjfaris View Post

    (x-5)^2=25

    This one is pretty easy, taking the square root of each side gives

     (x-5)^2=25

     x-5=\pm 5

     x=5\pm 5

     x=0,10
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  3. #3
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    Quote Originally Posted by mjfaris View Post
    How do I solve these using the square root property?

    x^2+4x+4=9

    (x-5)^2=25
    HI

    (x+2)^2=9

    x+2=\pm 3

    x=-2\pm 3

    (x-5)^2=25

    x-5=\pm 25

     <br />
x=5\pm 25 <br />
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  4. #4
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    Quote Originally Posted by mathaddict View Post
    HI

    (x+2)^2=9

    x+2=\pm 3

    x=-2\pm 3

    (x-5)^2=25

    x-5=\pm 25

     <br />
x=5\pm 25 <br />
    You didn't square root 25.
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