# Math Help - Solving quadratic equations/square root property

1. ## Solving quadratic equations/square root property

How do I solve these using the square root property?

x^2+4x+4=9

(x-5)^2=25

2. Originally Posted by mjfaris

(x-5)^2=25

This one is pretty easy, taking the square root of each side gives

$(x-5)^2=25$

$x-5=\pm 5$

$x=5\pm 5$

$x=0,10$

3. Originally Posted by mjfaris
How do I solve these using the square root property?

x^2+4x+4=9

(x-5)^2=25
HI

$(x+2)^2=9$

$x+2=\pm 3$

$x=-2\pm 3$

$(x-5)^2=25$

$x-5=\pm 25$

$
x=5\pm 25
$

4. Originally Posted by mathaddict
HI

$(x+2)^2=9$

$x+2=\pm 3$

$x=-2\pm 3$

$(x-5)^2=25$

$x-5=\pm 25$

$
x=5\pm 25
$
You didn't square root 25.