# Percentage problem

• Dec 2nd 2009, 12:49 PM
sri340
Percentage problem
Arnold sold two houses, each for $265,000. He made a profit of 30% on one house, and sold the other at a 30% loss. What total percent did he lose on the sale of both houses? • Dec 2nd 2009, 01:33 PM masters Quote: Originally Posted by sri340 Arnold sold two houses, each for$265,000. He made a profit of

30% on one house, and sold the other at a 30% loss. What total
percent did he lose on the sale of both houses?

Hi sri340,

I hope I interpret your problem correctly.

If he received $265,000 on the sale of house (1) which included a 30% profit, then the original cost of the house was: $265000=H_1+.3x$ $H_1=203846.15$ If he received$265000 on the sale of house (2) which included a 30% loss, then the original cost of the house was:

$265000=H_2-.3x$

$H_2=378571.43$

So, the original worth of both houses was $582,417.58. He sold them both for 2($265,000)= $530,000. That's a loss of$52,417.58.

The % of loss is $\frac{52417.58}{582417.58} \approx 9$%.