Rewriting equation

**BabyMilo** · December 2nd 2009, 10:45 AM

$2^x+28*(2^{-x})=11<br />$

show how this can be rewritten as

$(2^x)^2-11*2^x+28=0$

thanks

**earboth** · December 2nd 2009, 10:56 AM

Originally Posted by BabyMilo

$2^x+28*(2^{-x})=11<br />$

show how this can be rewritten as

$(2^x)^2-11*2^x+28=0$

thanks

$2^x+28*(2^{-x})=11~\implies~2^x+\dfrac{28}{2^x}-11=0<br />$

Now multiply both sides of the equation by $2^x$ and you'll get the given result at once.

Thread: Rewriting equation

LinkBack

Thread Tools

Display

Rewriting equation

Similar Math Help Forum Discussions

Rewriting an equation.

Rewriting Equation

Rewriting an equation into the form of Sin(a+b)

Rewriting an equation

Rewriting function equation

Search Tags