$\displaystyle 2^x+28*(2^{-x})=11

$

show how this can be rewritten as

$\displaystyle (2^x)^2-11*2^x+28=0$

thanks

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- Dec 2nd 2009, 10:45 AMBabyMiloRewriting equation
$\displaystyle 2^x+28*(2^{-x})=11

$

show how this can be rewritten as

$\displaystyle (2^x)^2-11*2^x+28=0$

thanks - Dec 2nd 2009, 10:56 AMearboth