simplification

**alyosha2** · December 2nd 2009, 06:43 AM

In textbook
$r(ar) = ar^2$

but

$r(ar) = rarr = ar^3$

what?

**skeeter** · December 2nd 2009, 06:58 AM

Originally Posted by alyosha2

In textbook
$r(ar) = ar^2$

but

$r(ar) = rarr = ar^3$

the r does not distribute over multiplication like it does for addition ...

$\textcolor{red}{r(ar) = r(ra) = (rr) a = r^2a = ar^2}$

..

**Stroodle** · December 2nd 2009, 07:05 AM

Originally Posted by alyosha2

In textbook
$r(ar) = ar^2$

but

$r(ar) = rarr = ar^3$

what?

$r(ar)\neq ar^3$

**alyosha2** · December 2nd 2009, 07:34 AM

so how do you geot from $r(ar)$ to $ar^2$ ?

**alyosha2** · December 2nd 2009, 07:53 AM

Originally Posted by alyosha2

so how do you geot from $r(ar)$ to $ar^2$ ?

$r(ar) = a(rr) = ar^2$

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