(x-3) is the Factor of f(x) 4x^2-7x-15
Help me is this correct of finding the other factor?
f(x)=l(x)q(x)+R
f(x)=(x-3)(4x+ax+5)+0
f(x)=x(4x+ax+5)-3(4x+ax+5)
f(x)=4x^2+ax^2+5x-12x-3ax-15
f(x)=(ax+5)=0 (12-3ax)=0
ax=-5 ax=4
Hello s2951I'm not sure where you get the term in the line that I've indicated. When you divide by , the result is simply .
If I may expand on acc100jt's solution a little:
If , then when we multiply out the RHS we get:
So, when we compare coefficients:
the coefficient ofand
the constant term:Check with the coefficient of :
, which is correctSo the other factor is
Grandad