Can someone explain the steps to squaring a radical similar to the one below?
2√3
Also, if I were to square: 9x/3 , what steps would I take?
Thanks.
Hi smiffstarr,
Remember, when you square a square root, you simply remove the radical sign.
$\displaystyle (2\sqrt{3})^2=2^2(\sqrt{3})^2=4(3)=12$
When you square a fraction, you square both the numerator and denominator, then simplify.
$\displaystyle \left(\frac{9x}{3}\right)^2=\frac{(9x)^2}{(3)^2}=\ frac{81x^2}{9}=9x^2$