whos eaten more pizza?

• Dec 1st 2009, 10:39 AM
janvi anish
whos eaten more pizza?
pls can you help on the following:
joe has eaten 2/5 of a pizza and sue has eaten 1/9 of a pizza..how many more times has joe eaten a pizza more than sue....the ans is 3/5 but i cannot do it..pls help
• Dec 1st 2009, 10:52 AM
Raoh
Quote:

Originally Posted by janvi anish
pls can you help on the following:
joe has eaten 2/5 of a pizza and sue has eaten 1/9 of a pizza..how many more times has joe eaten a pizza more than sue....the ans is 3/5 but i cannot do it..pls help

He only ate $\displaystyle \frac{2}{5}$ of a pizza,not all of it.(Thinking)
• Dec 1st 2009, 10:55 AM
janvi anish
yes... joe only ate 2/5 of the pizza... not all of it...
• Dec 1st 2009, 10:58 AM
Raoh
Quote:

Originally Posted by janvi anish
yes... joe only ate 2/5 of the pizza... not all of it...

yes,but you're asking "how many more times has joe eaten a pizza (a whole one) more than sue",how's that possible(Thinking)?
(or probably i haven't understood what you meant in your question(Itwasntme))
• Dec 1st 2009, 11:00 AM
janvi anish
i dont get it either... it was a question 4 my revision...

i think ur meant 2 do something with the 2 ans... (divide them... but it still doesnt get the correct ans... so i dont no how 2 work it out...)
• Dec 1st 2009, 11:23 AM
Raoh
well, $\displaystyle \frac{3}{5}$ is only what's left from joe's pizza(Rofl), $\displaystyle \left (1-\frac{2}{5} \right )=\frac{3}{5}$.
• Dec 1st 2009, 11:52 AM
Soroban
Hello, janvi anish!

Quote:

Joe has eaten $\displaystyle \frac{2}{5}$ of a pizza and Sue has eaten $\displaystyle \frac{1}{9}$ of a pizza.

How many more times has Joe eaten a pizza more than Sue?

The answer is $\displaystyle \frac{3}{5}.$ . . . . . This is wrong!

How does $\displaystyle \frac{2}{5}$ compare to $\displaystyle \frac{1}{9}$ ?

We have: .$\displaystyle \frac{\:\dfrac{2}{5}\:}{\dfrac{1}{9}} \;=\;\frac{2}{5}\cdot\frac{9}{1} \:=\:\frac{18}{5}$

Joe has eaten $\displaystyle 3.6$ times as much pizza as Sue ate.

• Dec 1st 2009, 12:56 PM
janvi anish
yes this is what we get also but on the answer it is saying 3/5 that is why we do not get it!!we have tried it many ways and get the same answer as you do but we think it is something to do with 'how many more times'
• Dec 1st 2009, 01:01 PM
Jameson
Quote:

Originally Posted by janvi anish
yes this is what we get also but on the answer it is saying 3/5 that is why we do not get it!!we have tried it many ways and get the same answer as you do but we think it is something to do with 'how many more times'

With the info you gave us Soroban's answer is correct. Answers in the back of the book aren't always correct!
• Dec 1st 2009, 01:05 PM
janvi anish
yes thanks but again we have another one similar...
joe has eaten 4/5 of a pizza, jane 1/8 how many more times has joe eaten a pizza than jane..this says that the answer is 2/5...but again i do not get it.....
i am sure it is in the wording somewhere....
• Dec 1st 2009, 01:12 PM
Paul46
I was going to say 13/45, the way i got it was 5*9 = 45, 9*2=18, 5*1 =5, 18-5 =13/45 , but reading the question properly it's 18/5= 3.6 like someone mentioned

Quote:

Originally Posted by janvi anish
yes thanks but again we have another one similar...
joe has eaten 4/5 of a pizza, jane 1/8 how many more times has joe eaten a pizza than jane..this says that the answer is 2/5...but again i do not get it.....
i am sure it is in the wording somewhere....

6.4
• Dec 2nd 2009, 02:17 AM
Raoh
Quote:

Originally Posted by janvi anish
yes thanks but again we have another one similar...
joe has eaten 4/5 of a pizza, jane 1/8 how many more times has joe eaten a pizza than jane..this says that the answer is 2/5...but again i do not get it.....
i am sure it is in the wording somewhere....

$\displaystyle \frac{\frac{4}{5}}{\frac{1}{8}}= \frac{4}{5}\times 8= \frac{32}{5}$
Therefore Joe has eaten 6,4 times as much pizza as Jane ate.