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Math Help - Write as a single logarithm.

  1. #1
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    Write as a single logarithm.

    3log2x + 1/2log2x - 2log2(x+1)

    I don't quite understand this. Ive gotten to "log2 x^3(x^1/2)/(x+1)^2"
    Any help would be great.
    Thanks.


    ~freak
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  2. #2
    Senior Member
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    Joining logs

    <br />
3log2x + (1/2)log2x - 2log2(x+1)<br />

    = <br />
log(2x)^3 + log(2x)^{1/2} - log{(2(x+1))}^2<br />

    = <br />
log(2x)^{3.5} - log{(2(x+1))}^2<br />

    = <br />
log \frac{(2x)^{3.5}}{{(2(x+1))}^2}<br />
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  3. #3
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    Thanks, i looked it over again and realized where i went wrong. I got the same asnwer as you did but the book had the top x to the power of 7/2. It took me to right after i posted this to realized that 3.5 and 7/2 were the same thing lol.
    Thanks for the help.

    ~freak
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