# Write as a single logarithm.

• November 30th 2009, 01:02 PM
freak
Write as a single logarithm.
3log2x + 1/2log2x - 2log2(x+1)

I don't quite understand this. Ive gotten to "log2 x^3(x^1/2)/(x+1)^2"
Any help would be great.
Thanks.

~freak
• November 30th 2009, 01:43 PM
qmech
Joining logs
$
3log2x + (1/2)log2x - 2log2(x+1)
$

= $
log(2x)^3 + log(2x)^{1/2} - log{(2(x+1))}^2
$

= $
log(2x)^{3.5} - log{(2(x+1))}^2
$

= $
log \frac{(2x)^{3.5}}{{(2(x+1))}^2}
$
• November 30th 2009, 02:04 PM
freak
Thanks, i looked it over again and realized where i went wrong. I got the same asnwer as you did but the book had the top x to the power of 7/2. It took me to right after i posted this to realized that 3.5 and 7/2 were the same thing lol.
Thanks for the help.

~freak