3log2x + 1/2log2x - 2log2(x+1)

I don't quite understand this. Ive gotten to "log2 x^3(x^1/2)/(x+1)^2"

Any help would be great.

Thanks.

~freak

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- Nov 30th 2009, 02:02 PMfreakWrite as a single logarithm.
3log2x + 1/2log2x - 2log2(x+1)

I don't quite understand this. Ive gotten to "log2 x^3(x^1/2)/(x+1)^2"

Any help would be great.

Thanks.

~freak - Nov 30th 2009, 02:43 PMqmechJoining logs

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= - Nov 30th 2009, 03:04 PMfreak
Thanks, i looked it over again and realized where i went wrong. I got the same asnwer as you did but the book had the top x to the power of 7/2. It took me to right after i posted this to realized that 3.5 and 7/2 were the same thing lol.

Thanks for the help.

~freak