Write as a single logarithm.

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November 30th 2009, 01:02 PM
freak

Write as a single logarithm.

3log2x + 1/2log2x - 2log2(x+1)

I don't quite understand this. Ive gotten to "log2 x^3(x^1/2)/(x+1)^2"
Any help would be great.
Thanks.

~freak
November 30th 2009, 01:43 PM
qmech

Joining logs

$<br /> 3log2x + (1/2)log2x - 2log2(x+1)<br />$

= $<br /> log(2x)^3 + log(2x)^{1/2} - log{(2(x+1))}^2<br />$

= $<br /> log(2x)^{3.5} - log{(2(x+1))}^2<br />$

= $<br /> log \frac{(2x)^{3.5}}{{(2(x+1))}^2}<br />$
November 30th 2009, 02:04 PM
freak

Thanks, i looked it over again and realized where i went wrong. I got the same asnwer as you did but the book had the top x to the power of 7/2. It took me to right after i posted this to realized that 3.5 and 7/2 were the same thing lol.
Thanks for the help.

~freak

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