# Math Help - Rational exponents problem

1. ## Rational exponents problem

I am supposed to factor
$3(x-2)^{\frac{1}{2}}$ from $12(x-2)^{\frac{3}{2}}-9(x-2)^{\frac{1}{2}}$

and my procedure was
$12(x-2)^{\frac{3}{2}}-9(x-2)^{\frac{1}{2}}$

$12(x-2)^{\frac{1}{2}+\frac{2}{2}}-9(x-2)^{\frac{1}{2}}$

$3(x-2)^{\frac{1}{2}}[4(x-2)-3]$

I checked my result but the book I am working with says the answer should be $3(x-2)^{\frac{1}{2}}(4x-11)$

Am I doing something wrong?? Please let me know.

2. Originally Posted by Alienis Back
I am supposed to factor
$3(x-2)^{\frac{1}{2}}$ from $12(x-2)^{\frac{3}{2}}-9(x-2)^{\frac{1}{2}}$

and my procedure was
$12(x-2)^{\frac{3}{2}}-9(x-2)^{\frac{1}{2}}$

$12(x-2)^{\frac{1}{2}+\frac{2}{2}}-9(x-2)^{\frac{1}{2}}$

$3(x-2)^{\frac{1}{2}}[4(x-2)-3]$

I checked my result but the book I am working with says the answer should be $3(x-2)^{\frac{1}{2}}(4x-11)$

Am I doing something wrong?? Please let me know.
your not doing anything wrong, $4(x-2)-3=4x-11$