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Math Help - make L subject

  1. #1
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    make L subject

     <br />
t=2(pi)\sqrt\frac{100-L}{g}<br />

    i have to make L subject. and find L when t=20 g =2

    i have g(\frac{t}{2pi})^2-100 = L


    not sure on this one? do i remove the sqrt first or bring the 2pi across first?
    thanks
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  2. #2
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    Quote Originally Posted by decoy808 View Post
     <br />
t=2(pi)\sqrt\frac{100-L}{g}<br />

    i have to make L subject. and find L when t=20 g =2

    i have g(\frac{t}{2pi})^2-100 = L


    not sure on this one? do i remove the sqrt first or bring the 2pi across first?
    thanks
    T = 2\pi \sqrt{\frac{100-L}{g}}<br />

    \frac{T}{2\pi} = \sqrt{\frac{100-L}{g}}

    \left(\frac{T}{2\pi}\right)^2 = \frac{100-L}{g}

    g \cdot \left(\frac{T}{2\pi}\right)^2 = 100-L

    L = 100 - g \cdot \left(\frac{T}{2\pi}\right)^2
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  3. #3
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    L=992.9475997 i get an error when i try put back into original equation. as i should be get in t=20
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  4. #4
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    Quote Originally Posted by decoy808 View Post
    L=992.9475997 i get an error when i try put back into original equation. as i should be get in t=20
    L = 100 - 2\left(\frac{20^2}{4\pi^2}\right) \approx 79.7<br />
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