When I try and solve the following I get the answer as log (x^-7/12) 1/3log(x^2) + log x - 3/4 log (x^3) In the book it says log (x^1/12)
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Originally Posted by davyboy123 When I try and solve the following I get the answer as log (x^-7/12) 1/3log(x^2) + log x - 3/4 log (x^3) In the book it says log (x^1/12) Note that, by the property , you have . Now use the property
Originally Posted by davyboy123 When I try and solve the following I get the answer as log (x^-7/12) 1/3log(x^2) + log x - 3/4 log (x^3) In the book it says log (x^1/12) I agree with you ... ... books have been wrong before.
Originally Posted by davyboy123 When I try and solve the following I get the answer as log (x^-7/12) Originally Posted by davyboy123 1/3log(x^2) + log x - 3/4 log (x^3) In the book it says log (x^1/12) Hi all another methode
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