1. ## [SOLVED] Correct Simplifaction?

Once again this is one of these things were it just absolutely confuses me

Example

$\displaystyle n^{\frac{3}{2}}\sqrt{n-1}$

I want to factor out a n^2, is this a correct way? I dont believe it is but however, I need to know simple things like this

$\displaystyle n^1n^{\frac{1}{2}}\sqrt{n-1}$

$\displaystyle n(n(n-1))^{\frac{1}{2}}$

$\displaystyle n^2(1-\frac{1}{n})^{\frac{1}{2}}$

2. Originally Posted by RockHard
Once again this is one of these things were it just absolutely confuses me

Example

$\displaystyle n^{\frac{3}{2}}\sqrt{n-1}$

I want to factor out a n^2, is this a correct way?
...
$\displaystyle n^2(1-\frac{1}{n})^{\frac{1}{2}}$ <<<< OK
...

3. Is that an OK, as in wth I did? Or as in that is fine? lol

or this way

$\displaystyle n^{\frac{3}{2}}({n-1})^{\frac{1}{2}}$

$\displaystyle ({n^4-n^3})^{\frac{1}{2}}$

Factoring out a n^4 and from the parenthesis because the square root of anything to a power of 4 is just the item squared?

$\displaystyle n^2({1-\frac{1}{n}})^{\frac{1}{2}}$

4. Originally Posted by RockHard
Is that an OK, as in wth I did? Or as in that is fine? lol

or this way

$\displaystyle n^{\frac{3}{2}}({n-1})^{\frac{1}{2}}$

$\displaystyle ({n^4-n^3})^{\frac{1}{2}}$

Factoring out a n^4 and from the parenthesis because the square root of anything to a power of 4 is just the item squared?

$\displaystyle n^2({1-\frac{1}{n}})^{\frac{1}{2}}$
What you did was OK, the result was OK - and: There may be a lot more ways to do this simplification. So choose that way which you know best!

5. Could you provide your input of the problem so I can get a view of your method if it differs, it may prove simpler for me to remember and etc...marking as solve anyway though