hello Miasmagasma,..
check your answer for question (a), the equation should be .
for question (d), do you mean that OP is perpendicular to L?
it would be better if you write your answer in details for part (b) and (c) so we can check it.
hello forum.
i'm studying maths as level on my own from text books and i'm getting stuck fairly often
please help me !!!
i'm stuck on part (d) of this question.
(a) find the equation of the line L through the point A(2,3) with gradient -1/2
answer = 2y = x +2
(b) show that the point P with coordinates (2 + 2t, 3 - t) will always lie on on L whatever the value of t.
which i can do. ( although i would be unsure how to word the answer in an exam).
(c) find the values of t such that the length AP is 5 units.
answer = √5 and -√5
now for...
(d) find the value of t such that OP is perpendicular ( where O is the origin ). Hence find the length of the perpendicular from O to L.
answer = the value of t is -1/5 but i have no idea how to calculate the length of O to L (OP).
can anyone walk me through it?
As Dedust suggested, this has slope 1/2, not -1/2.
Once you have the correct equation, just put x= 2+ 2t, y= 3- t into the equation and show that it is true no matter what t is.(b) show that the point P with coordinates (2 + 2t, 3 - t) will always lie on on L whatever the value of t.
which i can do. ( although i would be unsure how to word the answer in an exam).
[quote](c) find the values of t such that the length AP is 5 units.
answer = √5 and -√5
now for...
(d) find the value of t such that OP is perpendicular ( where O is the origin ). Hence find the length of the perpendicular from O to L.
answer = the value of t is -1/5 but i have no idea how to calculate the length of O to L (OP).
I think you should recheck (c) and (d) with the correct equation
Once you have the correct value of t, put it into the given equations to find x and y. Then use the formula to find the length.can anyone walk me through it?