1. ## Solve the problem.

The product of two consecutive integers is 41 more than their sum. Find the integers

2. I see it as

$x+(x+1)=a$

$x(x+1) = a+41$

Can you solve?

3. Originally Posted by pickslides
I see it as

$x+(x+1)=a$

$x(x+1) = a+41$

Can you solve?
i need help

4. Originally Posted by westdivo
i need help
Where are you stuck? What don't you understand?

5. Originally Posted by westdivo
i need help
To learn how the previous poster did the translation, try the following:

Translating Word Problems

"Number" Word Problems

To learn how to multiply out the parenthetical, try here.

To learn how to factor the resulting quadratic (x^2 - x - 42), try here.

To learn how to solve quadratics in general (including factored ones), try here.

That should cover any difficulties you're having. If not, please reply with a clear listing of your steps and reasoning so far. Thank you!

6. Originally Posted by westdivo
The product of two consecutive integers is 41 more than their sum. Find the integers
if x is the smaller integer then x + 1 is the larger integer:
x(x + 1) = x + (x + 1) + 41
x^2 - x - 42 = 0
x = 7 or -6
x + 1 = 8 or -5