I need help finding the inverse for this function

$\displaystyle g:[-1,\infty) \rightarrow, g(x) = x^2+2x$

What I've done so far.

Let $\displaystyle g(x) = y$

$\displaystyle y=x^2+2x$

Swap x and y, and solve for y

$\displaystyle x=y^2+2y$

$\displaystyle x=y(y+2)$

I'm stuck here, can anyone please help?

Nevermind, I got it, had to complete the square!