Hello, JaredMims!

A balloon is rising vertically above a level road at a constant rate of 1 ft/sec.

Just when the balloon is 65 feet above the ground,

a bicycle moving at a constant rate of 17 ft/sec passes under it.

(a) What is the distance between the balloon and the bicyclist three seconds later? Code:

A *
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17t

The balloon is at , rising at 1 ft/sec.

In the next seconds, it rises feet to

. . feet.

The cyclist is at , moving at 17 ft/sec.

In the next seconds, it moves feet to

. .

In 3 seconds, the balloon is 68 feet high, the cyclist moved 51 feet.

Pythagorus give us the distance: .

(b) What is the distance between the balloon and the bicyclist after another 3 seconds have passed?

After 6 seconds, the balloon is 71 feet high, the cyclist moved 102 feet.

Pythagorus says: .