Using the information given
Divide by 3 and take the 5th root.
Find the tenth term of a geometric sequence.
the first term is 3 the 6th term is root3/9
i stuck on the calucation for finding R
tn=ar^n-1
t6= root3/9 = 3(r)^5
(3^-1/2)/3^2=3(r)^5 <-- stuck
I checked the answer on my workbook .It says.
(3^-1/2)/3^3=r^5
3^-5=r^5
then it suddenly jumps right into r= 3^-1/2
i do not understand how they get rid of the exponent 5 in the workbook and if i factor out the 9 to 3^2, then how can i continue? will the answer be equivalent?