geometric sequence help
Find the tenth term of a geometric sequence.
the first term is 3 the 6th term is root3/9
i stuck on the calucation for finding R
t6= root3/9 = 3(r)^5
(3^-1/2)/3^2=3(r)^5 <-- stuck
I checked the answer on my workbook .It says.
then it suddenly jumps right into r= 3^-1/2
i do not understand how they get rid of the exponent 5 in the workbook and if i factor out the 9 to 3^2, then how can i continue? will the answer be equivalent?
Using the information given
Divide by 3 and take the 5th root.
I am having trouble following your notation. Please use parentheses to clear up confusion.
Originally Posted by hovermet
If you mean then cancel out a 3 from both sides, then take the 5th root of both sides.