Are these correct?

**SailorCardKnight** · November 24th 2009, 05:44 AM

Did I do these problems right? I just wanted to be sure.

Ignore number 7, I found out that one is correct. Sorry for my crappy handwriting, I tried to write these as neat as possible.

Scanned image..

**Raoh** · November 24th 2009, 06:11 AM

check your answer in 6.
u should get $-2\left ( x-4 \right )\left ( x-3 \right )$ .
answer 7,Yes.
Check ur answer in 8,u should get $-5x^2+5x-4$ .
Check ur answer in 9, u should get $6x^3-5x^2-16x+15$ .

**Stroodle** · November 24th 2009, 06:15 AM

Also, the slope of the first one is $\frac{9}{2}$ not $-\frac{9}{2}$ as a negative divided by a negative yields a positive

**SailorCardKnight** · November 24th 2009, 06:19 AM

Thanks guys. Now to go back and see where I did wrong.

**SailorCardKnight** · November 24th 2009, 11:40 AM

Sorry to double post but...

I looked at the answers you gave me to see where I messed up. I see where I messed up on 8 and 9 (I mixed up the signs), but i'm not getting how you got that answer for 6.

**earboth** · November 24th 2009, 12:08 PM

Originally Posted by SailorCardKnight

Sorry to double post but...

I looked at the answers you gave me to see where I messed up. I see where I messed up on 8 and 9 (I mixed up the signs), but i'm not getting how you got that answer for 6.

You start here:
$-2x^2+14x-24$ and then the next step isn't correct:

$-(2x^2-14x+24) = -(2x^2-8x-6x+24)$

$-(2x(x-4)-6(x-4))$

I'll leave the rest for you.

**Raoh** · November 24th 2009, 12:12 PM

first you didn't factorize well with $-1$ .
$-2x^2+14x-24=-1(2x^2-14x+24)$

**SailorCardKnight** · November 24th 2009, 12:17 PM

*smacks forehead*

Now I get what I did wrong, thanks guys.

**Raoh** · November 24th 2009, 12:21 PM

also why not factorizing with $-2$
$-2(x^2-7x+12)$ = $=-2(x-4)(x-3)$ .

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