$\displaystyle \sqrt{\frac{1}{16}}, \sqrt{\frac{2}{16}},\sqrt{\frac{3}{16}}, \sqrt{\frac{4}{16}}, \sqrt{\frac{5}{16}}, \sqrt{\frac{6}{16}}...$ Is this a geometric progression? Thanks
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Originally Posted by rainer $\displaystyle \sqrt{\frac{1}{16}}, \sqrt{\frac{2}{16}},\sqrt{\frac{3}{16}}, \sqrt{\frac{4}{16}}, \sqrt{\frac{5}{16}}, \sqrt{\frac{6}{16}}...$ Is this a geometric progression? Thanks a geometric sequence has a common ratio ... $\displaystyle \frac{a_{n+1}}{a_n} = r$ for any $\displaystyle n$.
NO, this isn't a Geometric progression as there is no common ratio. i-e 2nd term/1st term IS NOT EQUAL TO thirdterm/second term.
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