A rectangle has a length 2 meters less than twice its width. When 5 meters is added to the width, the result is a square with an area of 144 square meters. Find the dimensions of the original rectangle. (w+5)*(2w-2)=144?
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original width :$\displaystyle w$ original length :$\displaystyle 2w-2$ New width: $\displaystyle w+5$ New area = 144 So $\displaystyle (w+5)(2w-2)=144$
Last edited by acc100jt; Nov 22nd 2009 at 11:17 PM.
Originally Posted by acc100jt original width :$\displaystyle w$ original length :$\displaystyle w-2$ New width: $\displaystyle w+5$ New area = 144 [Note that the length is not changed] So $\displaystyle (w+5)(w-2)=144$ Wouldnt it be (w+5)(2w-2)=144?
LOL, my bad, i didn't see the "twice" (w+5)(2w-2)=144 is correct
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