Quote:

A rectangle has a length 2 meters less than twice its width. When 5 meters is added to the width, the result is a square with an area of 144 square meters. Find the dimensions of the original rectangle.

(w+5)*(2w-2)=144?

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- Nov 22nd 2009, 10:15 PMm0nkeysenseiquadratic area word problemQuote:

A rectangle has a length 2 meters less than twice its width. When 5 meters is added to the width, the result is a square with an area of 144 square meters. Find the dimensions of the original rectangle.

(w+5)*(2w-2)=144? - Nov 22nd 2009, 10:27 PMacc100jt
original width :$\displaystyle w$

original length :$\displaystyle 2w-2$

New width: $\displaystyle w+5$

New area = 144

So $\displaystyle (w+5)(2w-2)=144$ - Nov 22nd 2009, 10:32 PMm0nkeysensei
- Nov 22nd 2009, 11:16 PMacc100jt
LOL, my bad, i didn't see the "twice"

(w+5)(2w-2)=144 is correct :)